Question
A man invested ₹40,000 in two schemes A and B offering
simple interest at the rate of 8% per annum and 10% per annum respectively. If the total interest earned after 2 years from both the schemes is ₹7,200 and the amount invested in scheme A is ₹x, find the value of x.Solution
Let the amount invested in scheme A be ₹x. Then the amount invested in scheme B = ₹(40,000 - x). The interest from scheme A: = (x × 8 × 2) / 100 = 0.16x. The interest from scheme B: = ((40,000 - x) × 10 × 2) / 100 = 0.2(40,000 - x) = 8,000 - 0.2x. Total interest = ₹7,200: 0.16x + 8,000 - 0.2x = 7,200 -0.04x + 8,000 = 7,200 -0.04x = -800 x = ₹20,000.
The following numbers form a series. Find the odd one out.
7, 11, 19, 35, 67, 131
Find the wrong number in the given number series,
54, 58, 67, 92, 139, 262
There are two wrong number series given in question and three relationships has been derived from that you have to answer the correct relationship betwe...
The following numbers form a series. Find the odd one out.
500, 1012, 963, 1185, 1154, 1218
27, 35, 51, 75, 109, 147
216, 432, 144, 288, 96, 191, 64
53, 57, 66, 82, 117, 143, 192
Find the wrong number in the given number series.
70, 94, 130, 182, 274, 406
Find the wrong number in given number series.
136, 184, 250, 304, 376, 456
98, 128, 162, 200, 244, 288
