Question
A sum of money was invested at an annual compound
interest rate of 8%, with interest compounded yearly. After 2 years, the total interest earned was Rs. 3,328. Determine the initial amount of money that was invested.Solution
Let assume the sum invested Rs. 'x' ATQ; Total amount recieved = x X (1 + 8/100) 2 or, (x X 3328) =Â Â x X (1 + 8/100) 2Â or, (x X 3328) =Â Â x X (27/25) 2Â Or, 625 X (x + 3328) = 729x Or, 625x + 2080000 = 729x Or, (729x - 625x) = 2080000 Or, 104x = 2080000 Or, x = 20000 Therefore, sum invested = Rs. 20,000 Hence, option d.
?% of 320 = 40% of 40 × 5
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
42% of 400 + 38% of 800 + ?2 = 728
What will come in place of (?) in the given expression.
{(60% of 250) + √144} ÷ (3² - 4) = ?- What will come in place of (?) in the given expression.
√324 + √121 – √49 = ? Determine the simplified value of following expression:
0.998 + 0.882 + 0.12Â
√225 + 27 × 10 + ? = 320
(26)2 = {(20% of 40% of 18200) ÷ ?} × 1664 ÷ 128Â
(2 ÷ 3) × (4 ÷ 12) × (? ÷ 10) × 45 × (1 ÷ 5) = (? ÷ 6) + (2 ÷ 5)
What is the value of 143 + 163 + 183 + … + 303?
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