Question
Vaishali invested Rs. (X + 3000) on compound interest of
r% p.a. compounded annually for 2 years and Tanushi invested Rs. (X – 2000) on simple interest of (r – 2)% p.a. for 3 years. The total interest received by both of them is together Rs. 12360. If Anuj invested Rs. (X + 8000) on simple interest for 3 years on 15% and received an interest of Rs. 13500, find the value of ‘r’.Solution
According to the question, Simple interest received by Anuj = Rs. 13500 (X + 8000) × 15% × 3 = 13500 (X + 8000) = 30000 X = 22000 Amount invested by Vaishali = Rs. 22000 + 3000 = Rs. 25000 Amount invested by Tanushi = 22000 – 2000 = Rs. 20000 The total interest received by Vaishali and Tanushi = Rs. 12360 [25000 × (1 + r/100)2 – 25000] + [20000 × (r – 2)% × 3] = 12360 25000 × (1 + r/100)2 – 25000 + 600(r – 2) = 12360 25000 × (1 + r2/10000 + r/50) – 25000 + 600(r – 2) = 12360 25000 + 2.5r2 + 500r – 25000 + 600(r – 2) = 12360 2.5r2 + 500r + 600r – 1200 = 12360 2.5r2 + 1100r = 13560 r2 + 440r – 5424 = 0 r2 + 452r – 12r – 5424 = 0 r(r + 452) – 12(r + 452) = 0 (r + 452)(r – 12) = 0 r = -452, 12 Rate of interest cannot be negative. So, r = 12  Â
?% of 740 – 8% of 650 = 7.2
Find the value of x.
 √441 ÷ 21+ √400 = 1 × x
√( (664+ √(136+ √(59+ √(21+ √(7+ √81) ) ) ) ) ) = ?
Ravi is 12 years younger than Surya. Ravi's age is 40% of the sum of his and Surya's age. What will be Surya's age 9 years hence?Â
40 × 5 + 27) × 9 = ?
What will come in the place of question mark (?) in the given expression?
1/5 of 6/3 of 3/2 of 1966 = ?
125 ÷ 5 + 14 × 4 = ? + 72 ÷ 4 – 35
4387897 – 3286871 – 51926 = ?
Find the simplified value of the given expression:
15 of 4 ÷ 3 × 4² + √49 – 12