Question
Vaishali invested Rs. (X + 3000) on compound interest of
r% p.a. compounded annually for 2 years and Tanushi invested Rs. (X β 2000) on simple interest of (r β 2)% p.a. for 3 years. The total interest received by both of them is together Rs. 12360. If Anuj invested Rs. (X + 8000) on simple interest for 3 years on 15% and received an interest of Rs. 13500, find the value of βrβ.Solution
According to the question, Simple interest received by Anuj = Rs. 13500 (X + 8000) Γ 15% Γ 3 = 13500 (X + 8000) = 30000 X = 22000 Amount invested by Vaishali = Rs. 22000 + 3000 = Rs. 25000 Amount invested by Tanushi = 22000 β 2000 = Rs. 20000 The total interest received by Vaishali and Tanushi = Rs. 12360 [25000 Γ (1 + r/100)2Β β 25000] + [20000 Γ (r β 2)% Γ 3] = 12360 25000 Γ (1 + r/100)2Β β 25000 + 600(r β 2) = 12360 25000 Γ (1 + r2/10000 + r/50) β 25000 + 600(r β 2) = 12360 25000 + 2.5r2Β + 500r β 25000 + 600(r β 2) = 12360 2.5r2Β + 500r + 600r β 1200 = 12360 2.5r2Β + 1100r = 13560 r2Β + 440r β 5424 = 0 r2Β + 452r β 12r β 5424 = 0 r(r + 452) β 12(r + 452) = 0 (r + 452)(r β 12) = 0 r = -452, 12 Rate of interest cannot be negative. So, r = 12 Β Β
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