Question

Sameer invested Rs. (R + 1000) at simple interest of 20%

Q: Answer-Sameer invested Rs. (R + 1000) at simple interest of 20% p.a. for 3 years. Ajeet invested Rs. (R - 4...

Simple interest Sum X rate of interest X time period in years 100 So, simple interest earned R 1000 X 20 X 3 100 Rs. 0.6R 600 And compound interest earned R - 4000 X 1 20100 3 - R - 4000 R - 4000 X 1.728 - 1 R - 4000 X 0.728 Rs. 0.728R - 2912 So, two cases are possible Case I simple interest compound interest So, 0.6R 600 0.728R - 2912 1080 Or, 2432 0.128R So, R 19000 Case II simple interest compound interest So, 0.6R 600 1080 0.728R - 2912 Or, 4592 0.128R So, R 35875 For statement I Since, R can take two values So, statement I is true. For statement II Again, since R 19,000 or 35875 which are greater than 10,000 So, statement II is false. For statement III Since, R has multiple values So, statement III is false.

p.a. for 3 years. Ajeet invested Rs. (R - 4000) at compound interest of 20% p.a. for 3 years. If the difference between interest earned from both investments is Rs. 1,080, then which of the following statement(s) is/are true? I. 'R' can take multiple values. II. The minimum value that 'R' can take is less than 10,000. III. 'R' must be an even number.

A Only I

B Only I and II

C Only II and III

D Only I and III

E None of these

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