Question
‘J’, ‘K’ and ‘L’, each of them invested Rs.
5000 at the rate of 18% p.a., 22% p.a. and 40% p.a., respectively for 6 years, 5 years and 3 years, respectively. Find the sum of simple interests received by them.Solution
ATQ, Simple interest received by ‘J’ = (5000 × 18 × 6)/100 = Rs. 5400 Simple interest received by ‘K’ = (5000 × 22 × 5)/100 = Rs. 5500 Simple interest received by ‘L’ = (5000 × 40 × 3)/100 = Rs. 6000 Required sum = (5000/100) × {(18 × 6) + (22 × 5) + (40 × 3)} = Rs. 16900
I. 2y2 – 19y + 35 = 0
II. 4x2 – 16x + 15 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 42x + 392 = 0
Equation 2: y² - 46y + 480 = 0
Equation 1: x² - 120x + 3500 = 0
Equation 2: y² - 110y + 3025 = 0
Find the coefficient of x³ in (2x − 3)⁶.
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 22x + 120 = 0
Equation 2: y² - 25y + 144 = 0
Find the value of 'x' and 'y' in the following equation:
7x - 2y = 46
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
l. 3x2 + 17x + 24 = 0
II. 2y2 + 15y + 27 = 0
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y.
I. x
I. 22x² - 97x + 105 = 0
II. 35y² - 61y + 24 = 0
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