Question
sum invested at a certain rate of compound interest,
compounded annually amounts to Rs.12,240 after 2 years and amounts to Rs. 17,625.6 after 4 years. If 60% of the sum is invested in the simple interest of 7p.a 10 years, then find the simple interest earned.Solution
Let the sum invested = Rs. 'K' Let the rate of interest = 'y'% p.a. Then, according to the question K X {1 + (y/100)} ² = 12,240 ....... (I) And K X {1 + (y/100)} ⁴ = 17625.6 ........ (II) On dividing equation (I) from equation (II), we have. {1 + (y/100)} ² = 1.44 Or, 1 + (y/100) = 1.2 Or (y/100) = 0.2 So, y = 20 Therefore, sum invested = 12240 ÷ {(100 +20)/100} ² = 12240 ÷ 1.44 = Rs. 8,500 so, sum invest at simple interest= 8500×60/100=5100 so simple interest earned =5100×7×10/100=3570rs
1219.98 ÷ 30.48 × 15.12 = ? × 2.16
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
`1804/898-:99/699xx749/751=?`
(√845 ×19.932+ √4230 ×14.385)/(√1765 ×4.877 ) = ?
Direction: Please solve the following expression and choose the closest option
`(13.022)^(2)+ (42.93)^(2)-(53.125)^(2)+(192.33xx14.88)=?- (88.44)^(2)- (42.03 xx 23.12)`
√49 + 6.66% of 1725 + 22² = ?² - √361
What approximate value will replace the question mark (?) in the following?
? =...
? = 49.97% of 38.09% of 1998.95
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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