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Let the sum invested = Rs. 'K' Let the rate of interest = 'y'% p.a. Then, according to the question K X {1 + (y/100)} ² = 12,240 ....... (I) And K X {1 + (y/100)} ⁴ = 17625.6 ........ (II) On dividing equation (I) from equation (II), we have. {1 + (y/100)} ² = 1.44 Or, 1 + (y/100) = 1.2 Or (y/100) = 0.2 So, y = 20 Therefore, sum invested = 12240 ÷ {(100 +20)/100} ² = 12240 ÷ 1.44 = Rs. 8,500 so, sum invest at simple interest= 8500×60/100=5100 so simple interest earned =5100×7×10/100=3570rs
Simplify the given expression
[1.5 × 1.5 × 1.5 + 2.7 × 2.7 × 2.7 + 4.8 × 4.8 × 4.8 – 3 × 1.5 × 2.7 × 4.8] / [1.5 × 1.5 +2.7 × 2.7 ...
654.056 + 28.9015 × 44.851 – 43.129 = ?
(18% of 360) ÷ 0.4 = ?
The value of 43-3× (4×6+12/3 ×6-4×5) +4?
168 163 153 138 118 ?
...1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2