Question
A man invested certain sum at simple interest of r% p.a.
such that it amounts to 160% of itself in 6 years. Find the interest earned when Rs. 2400 is invested at simple interest of r% p.a. for 3 years.Solution
Let the sum invested be Rs. ‘P’ Therefore, interest earned in 6 years = 1.6P – P = Rs. 0.6P ATQ; 0.6P = (P × r × 6) ÷ 100 Or, r = 60 ÷ 6 Or, r = 10 So, required interest earned = (2400 × 10 × 3) ÷ 100 = Rs. 720
More Simple and compound interest Questions
182 + 10 × 12 - ? = 312
53 – 8 = ? + 126
2850 ÷ 2.5 - ? × 42 = 300
Determine the value of ‘x’ if x% of 500 plus {1250 ÷ x of 10} × 5 equals 130
Evaluate
32 ÷ 2 of 7 of [14 ÷ 7 of (6 ÷ 3 + 5)] + (6 ÷ 2 + 1)
What will come in place of (?) in the given expression.
[(24 ÷ 3) + (18 × 2)] - 5 = ?666(2/3)% of 30 - 116(2/3)% of 90 =?
√ [? x 11 + (√ 1296)] = 16
What will come in the place of question mark (?) in the given expression?
{122 + (66/4) + (252/8)} ÷ 8 = (?)1/2
(62 + 82 ) X ? = 80% of 500 - 25 X 4
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