A man deposited 25% of his salary to a bank which offers compound interest at the rate of 10% p.a. If the interest earned by him from the bank after 2 years is Rs. 3570, find the monthly expenditure of the man which is 56% of his monthly salary.
Let the amount of money deposited in the bank be Rs. ‘x’. So, x × [(1.1)2 – 1] = 3570 0.21x = 3570, x = 17000 So, monthly income of man = 17000/0.25 = Rs. 68000 Required monthly expenditure of man = 56% of 68000 = Rs. 38080
`(sqrt(960.87)xx9.932+sqrt(629.998)xx26.385)/(sqrt(1028.902)xx4.977)=?`
2280.03 ÷ 59.98 x 59.9 = ? + 30.32
(98.999)2 - (9.9)2 - (14.9)2 = ?
(22.03 + 89.98) ÷ 14.211 = 89.9 – 25.23% of ?
(519.98 + ?) ÷ 13.01 = √440 + 20.0
36.22 of 249.98% + 299.99 ÷ 30.18 = ?
5999.93 ÷ 60.005 × 70.002 = ? × 24.9
? = 23.08 + 19.99 × 28.07
20.99 × √4.09 × 30.09 = ? × √195.99 × 15.09
(20.98% of 299.99) - 4.998 = √?
