Question
The interest earned when a sum is invested at simple
interest of 12% p.a., for 3 years, is Rs. 4500. What will be the total amount received after 2 years on investing the same sum at compound interest (compounded annually) of 10% interest p.a.?Solution
Let the sum invested = Rs. Y According to the question, (Y × 3 × 12) ÷ 100 = 4500 So, Y = (4500/0.36) = 12500 So, required amount received = 12500(1 + 10/100)2 = 12500(11/10)2 = Rs. 15125
I. x2 – 39x + 360 = 0
II. y2 – 36y + 315 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
What will be the product of smaller roots of both equations.
I. 3x2 - 14x + 15 = 0
II. 15y2 - 34 y + 15 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
Equation 1: 2x2 - 21x + 54 = 0
Equation 2: 4y2 - 23y + 15 = 0
Difference between the roots of equation 1 is approx...
I. 4x² - 15x + 9 = 0
II. 20y² - 23y + 6 = 0
- For what value of a does the quadratic equation x² + ax + 81 = 0 have real and identical roots?
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
I. 3x2 + 3x - 60 = 0
II. 2y2 - 7y + 5 = 0
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