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Let the farmer give Rs x to the 18 years old son and the remaining Rs (1,22,000 - x) to his 20 years old son. Now, [x(1+(20/100))]4 = (1,22,000 - x) (1+(20/100))2 ⇒ [x(120/100)]2 = (1,22,000 - x) ⇒ [x(6/5)]2 = (1,22,000 - x) ⇒ x(36/25) = (1,22,000 - x) ⇒ ((36/25)+1) x = 1,22,000 ⇒ ((36 + 25)/25) x = 1,22,000 ⇒ x = (1,22,000 × 25)/61 = 50,000 ∴ x = Rs 50,000 For 18 years old son = Rs 50,000 For 20 years old son = Rs 72,000 Alternate shortcut method: They will get the sum in 2nd to 1st child in the ratio of = (1+R/100)(difference between their age) = (1+(20/100))(20-18) = (6/5)2 = 36/25 So for 18 years old(1st child) , sum = [25/(36+25)] × 122000 = (25/61) × 122000 = 50000 & for 20 years old(2nd child) , sum = [36/(36+25)] × 122000 = (36/61) × 122000 = 72000
Consider the following pairs:
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Which Indian ministry collaborated with LEAD at Krea University to create a new inventory of knowledge products in October 2024?
Gayatribala Panda won the Sahitya Akademi Awards 2022 for the Odia language for which type of literary work?
Which country has recently been selected to chair the 68th Session of the UN Commission on Narcotic Drugs (CND)?