Question
Three series are provided below. You need to determine
the values of A, B, and C and subsequently establish a relationship among them. I: 4, 10, 32, 130, (6A + 4) II: 47, 119, 167, 287, (5B + 4) III: 300, 150, 225, 7.5C, 1968.75Solution
ATQ, Series (i), 4 × 2 + 2 = 10 10 × 3 + 2 = 32 32 × 4 + 2 = 130 130×5+2=652 6A+ 4 = 652 6A = 648 A = 108 Series (ii), 72 - 2 = 47 112 - 2 = 119 132 - 2 = 167 172 - 2 = 287 192 - 2 = 359 5B + 4 = 359 5B = 355 B = 71 Series (iii), 300 × 0.5 = 150 150 × 1.5 = 225 225 × 2.5 = 562.5 562.5 × 3.5 = 1968.75 7.5C = 562.5 C = 75 Thus, A > C>B .
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