Question
Solution A has milk and water in 1:1 ratio. Solution B
contains them in 5:3 ratio. 40 litres of A and 32 litres of B are mixed. Find the milk to water ratio in the resulting solution.Solution
ATQ,
Milk in A = (1/2) × 40 = 20 litres
Water in A = (1/2) × 40 = 20 litres
Milk in B = (5/8) × 32 = 20 litres
Water in B = (3/8) × 32 = 12 litres
Required ratio = (20 + 20) : (20 + 12) = 40 : 32 = 5 : 4
?% of 1499.89 + 54.14 × 8 = 25.05% of 5568.08
? = 41.92% of (34.92 x 40.42) + 29.78% of 399.84
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(15.87% of 79.98 + 19.69% of 64.22) × 4.83 = ?
? + 163.99 – 108.01 = 25.01 × 6.98
80.09 * √144.05+ ? * √224.87 = (2109.09 ÷ √1368.79) * 19.89
(15.15 ×  31.98) + 30.15% of 719.99 = ? + 124.34
(124.99)² = ?
6.992 + (2.01 × 2.98) + ? = 175.03
(627.98 ÷ 3.98 + 11.01 X 12.98 - ?) ÷ √623 = (178.98 + 37.08) ÷ 23.98Â