Question
A total sum of Rs. 6720 was to be divided among X, Y,
and Z in the ratio 10:14:16 respectively. However, it was mistakenly distributed in the ratio 9:11:12 respectively. Calculate the difference between the amount X was supposed to get and the amount actually received by Y.Solution
ATQ,
Amount supposed to be received by 'X' = 6720 × (10/40) = Rs. 1680
Actual amount received by 'Y' = 6720 × (11/32) = Rs. 2310
So, required difference = 2310 - 1680 = Rs. 630
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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