Question
The ratio of the present ages of ‘M’ and ‘N’ is
5:3, respectively. 4 years ago, the ratio of their ages was 2:1. The sum of the present ages of ‘M’ and ‘N’ is:Solution
Let the present ages of ‘M’ and ‘N’ be ‘5x’ and ‘3x’ years, respectively ATQ; (5x - 4)/(3x - 4) = 2/1 Or, 5x - 4 = 6x - 8 Or, x = 4 Now, sum of present ages of ‘M’ and ‘N’ = 5 × 4 + 3 × 4 = 32
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