Question
The ratio of the present ages of βAβ and βBβ is 4:5, respectively. After 8 years, the ratio of their ages will become 5:6. The sum of the present ages of βAβ and βBβ is:
Solution
Let the present ages of βAβ and βBβ be β4xβ and β5xβ years, respectively ATQ; (4x + 8)/(5x + 8) = 5/6 Or, 24x + 48 = 25x + 40 Or, x = 8 Now, sum of present ages of βAβ and βBβ = 4 Γ 8 + 5 Γ 8 = 72
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