Question
The ratio of two numbers βAβ and βBβ is 9:7,
respectively. If 6 is subtracted from each of βAβ and βBβ, then the ratio of βAβ and βBβ becomes 3:2. The sum of βAβ and βBβ is:Solution
Let the two numbers βAβ and βBβ be β9xβ and β7xβ, respectively ATQ; (9x - 6)/(7x - 6) = 3/2 Or, 18x - 12 = 21x - 18 Or, 3x = 6 Or, x = 2 Now, sum of βAβ and βBβ = 9 Γ 2 + 7 Γ 2 = 32
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