Question
Four numbers βWβ, βXβ, βYβ and βZβ are
such that βWβ is double of βXβ, βYβ is half of βXβ, and βZβ is the average of βWβ and βYβ. If the sum of these four numbers is 950, then find the value of βZβ.Solution
Let the value of βXβ be β4xβ So, value of βWβ = 2 Γ 4x = β8xβ So, value of βYβ = 4x/2 = β2xβ So, value of βZβ = (8x + 2x)/2 = 10x/2 = β5xβ ATQ; 8x + 4x + 2x + 5x = 950 Or, 19x = 950 Or, x = 50 So, the value of βZβ = 5x = 5 Γ 50 = 250
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