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      Question

      Four numbers β€˜A’, β€˜B’, β€˜C’ and β€˜D’ are

      such that β€˜A’ is half of β€˜B’, β€˜C’ is double of β€˜A’, and β€˜D’ is equal to the average of β€˜A’, β€˜B’ and β€˜C’. If the sum of these four numbers is 800, then find the value of β€˜D’.
      A 180 Correct Answer Incorrect Answer
      B 250 Correct Answer Incorrect Answer
      C 120 Correct Answer Incorrect Answer
      D 200 Correct Answer Incorrect Answer

      Solution

      Let the value of β€˜B’ be β€˜6x’ So, value of β€˜A’ = 6x/2 = β€˜3x’ So, value of β€˜C’ = 2 Γ— 3x = β€˜6x’ So, value of β€˜D’ = (3x + 6x + 6x)/3 = 15x/3 = β€˜5x’ ATQ; 3x + 6x + 6x + 5x = 800 Or, 20x = 800 Or, x = 40 So, the value of β€˜D’ = 5x = 5 Γ— 40 = 200

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