Question
Four numbers ‘A’, ‘B’, ‘C’ and ‘D’ are such that ‘A’ is half of ‘B’, ‘C’ is double of ‘A’, and ‘D’ is equal to the average of ‘A’, ‘B’ and ‘C’. If the sum of these four numbers is 800, then find the value of ‘D’.
Solution
Let the value of ‘B’ be ‘6x’ So, value of ‘A’ = 6x/2 = ‘3x’ So, value of ‘C’ = 2 × 3x = ‘6x’ So, value of ‘D’ = (3x + 6x + 6x)/3 = 15x/3 = ‘5x’ ATQ; 3x + 6x + 6x + 5x = 800 Or, 20x = 800 Or, x = 40 So, the value of ‘D’ = 5x = 5 × 40 = 200
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