Question
Four numbers βAβ, βBβ, βCβ and βDβ are
such that βAβ is half of βBβ, βCβ is double of βAβ, and βDβ is equal to the average of βAβ, βBβ and βCβ. If the sum of these four numbers is 800, then find the value of βDβ.Solution
Let the value of βBβ be β6xβ So, value of βAβ = 6x/2 = β3xβ So, value of βCβ = 2 Γ 3x = β6xβ So, value of βDβ = (3x + 6x + 6x)/3 = 15x/3 = β5xβ ATQ; 3x + 6x + 6x + 5x = 800 Or, 20x = 800 Or, x = 40 So, the value of βDβ = 5x = 5 Γ 40 = 200
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