Question
Find the fourth proportion of (2k - 2), (4k - 4) and
(6k - 6). (Note: 'k' is the largest single-digit prime number.)Solution
'k' = 7 2k - 2 = 2 × 7 - 2 = 12 4k - 4 = 4 × 7 - 4 = 24 6k - 6 = 6 × 7 - 6 = 36 Let the fourth proportion be 'm'. 12 : 24 :: 36 : m So, 12 × m = 24 × 36 Or, 'm' = 72
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