Question
Find the fourth proportion of (2k + 1), (4k + 2) and
(6k + 3). (Note: 'k' is the smallest two-digit prime number.)Solution
'k' = 11 2k + 1 = 2 × 11 + 1 = 23 4k + 2 = 4 × 11 + 2 = 46 6k + 3 = 6 × 11 + 3 = 69 Let the fourth proportion be 'm'. 23 : 46 :: 69 : m So, 23 × m = 46 × 69 Or, 'm' = 138
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