Question
A total of Rs. ‘K’ was to be distributed among Ravi,
Raju, and Rina in ratio of 5:6:7 respectively but due to some error the money was falsely distributed in ratio of 4:6:8 respectively such that Ravi received Rs. 1800 less. Find the value of 2K.Solution
Let the total amount [K] be Rs. 18x
So, amount which Ravi was supposed to receive = 18x × (5/18) = Rs. 5x
Amount which was actually received by Ravi = 18x × (4/18) = Rs. 4x
ATQ,
5x - 4x = 1800
⇒ x = 1800
Also,
K = 18x = 18 × 1800 = Rs. 32400
Therefore, required value,
2K = 2 × 32400 = ₹64800
15.08% of (133.13 + 146.928) + 8.033 - (8.98 of 6.01) = ? of (46.09 - 20.98)
75.22 of 219.98% + 359.99 ÷ 18.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
(9116.89 – 8024.89 + 902.95) × 14 = 1800 × ?
5.25 x 4.09 + 3.99 x 9.67 + 6.01 x 14.88 = ?
What approximate value will come in place of the question mark (?) in the following question?
(2160.23 ÷ 35.98) + (600.32 ÷ 23.9) + 1744.11 = ?
20.06% of 359.89 - 15.95 X ? + 18.07 X 14.95 = 48.87 X 6.02
(5/9 of 2700.11) + (49.78% of 143.88) - (2/7 of 489.89) = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
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