In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. Quantity-I: A shopkeeper sells an article at a profit of 20%. If he had bought it at 10% less cost and sold it for Rs. 18 less, he would have gained 25%. Find the original cost price of the article. Quantity-II: A sum of money triples itself in 8 years under simple interest. Find the initial sum of money if the interest earned on it in 5 years is Rs. 300?

Quantity I: Let original cost price of article = ‘x’ Original selling price = 1.20x New cost price = 0.90x New selling price = 1.20x - 18 ATQ, 1.20x - 18 = 1.25 × 0.90x Or, 1.20x - 18 = 1.125x Or, 0.075x = 18 Or, x = 18 / 0.075 Or, x = 240 So, Quantity I = 240 Quantity II: Let initial sum of money = ‘P’ Amount in 8 years = 3P Simple Interest in 8 years = 3P - P = 2P Rate of interest per annum = (2P × 100) / (P × 8) = 25% ATQ, Simple interest in 5 years = (P × 25 × 5) / 100 = 300 Or, 125P / 100 = 300 Or, 5P / 4 = 300 Or, P = (300 × 4) / 5 Or, P = 240 So, Quantity II = 240 Therefore, Quantity I = Quantity II Hence, the correct answer is D.