Question
In the question, two Quantities I and II are given. You
have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option. Quantity-I: Length of a rectangle is 1.2 times of side of a square whose perimeter is 80 cm. Find the area of rectangle if its breadth is 10 cm less than its length. Quantity-II: Find the area of a square whose side (in cm) is equal to 3rd multiple of 5.Solution
Quantity I: Side of square = (80/4) = 20 cm Length of rectangle = 1.2 X 20 = 24 cm Breadth of rectangle = 24 - 10 = 14 cm Area of rectangle = 24 X 14 = 336 cm2 So, Quantity I = 336 cm2 Quantity II: We know that, 3rd multiple of 5 = 15 So, side of square = 15 cm Area of square = (15) 2 = 225 cm2 So, Quantity II = 225 cm2 Therefore, Quantity-I > Quantity-II Hence, option a.
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