Question
The current ages of three
friends, Aman, Bheema, and Chintu, are represented as (p−3), p, and (2p−6) years, respectively. It is given that Bheema's current age is 3 years less than 50% of the sum of Aman’s and Chintu’s current ages. Quantity I: Determine Chintu's present age. Quantity II: Calculate the average of the current ages of Aman, Bheema, and Chintu. In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.Solution
ATQ, We have, p + 3 = (1/2) × (p - 3 + 2p - 6) Or, 2p + 6 = 3p - 9 Or, 'p' = 15 Quantity I: Present age of 'Chintu' = 2p - 6 = 2 × 15 - 6 = 24 years So, Quantity I = 24 years Quantity II: Average present age = (1/3) × (p - 3 + p + 2p - 6) = (1/3) × (4p - 9) = (1/3) × (4 × 15 - 9) = (51/3) = 17 years So, Quantity II = 17 years Therefore Quantity I > Quantity II
Solve the following expression and calculate the approximate value.
398% of 388 + 129% of 323.89 – 430.93
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
156.76 + 14.08² + ?³ = √625.12 * 26.87
1299.999 ÷ 325.018 × 24.996 = ?
24.01 X 24.99 - ?% of 599.96 = 14.92 X 8.12
? = 782.24 + 1276.97 – 4.992
(9.013 – 15.04) = ? + 9.98% of 5399.98
Solve the given equation for ?. Find the approximate value.
[(49.88% of 320.11) × (34.85% of 460.24)] ÷ √783.94 = ?
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value....