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    Question

    The current ages of three

    friends, Aman, Bheema, and Chintu, are represented as (p−3), p, and (2p−6) years, respectively. It is given that Bheema's current age is 3 years less than 50% of the sum of Aman’s and Chintu’s current ages. Quantity I: Determine Chintu's present age. Quantity II: Calculate the average of the current ages of Aman, Bheema, and Chintu. In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.
    A Quantity-I > Quantity-II Correct Answer Incorrect Answer
    B Quantity-I < Quantity-II Correct Answer Incorrect Answer
    C Quantity-I ≥ Quantity-II Correct Answer Incorrect Answer
    D Quantity-1 ≤ Quantity-II Correct Answer Incorrect Answer
    E Quantity-I = Quantity-II or No relation Correct Answer Incorrect Answer

    Solution

    ATQ, We have, p + 3 = (1/2) × (p - 3 + 2p - 6) Or, 2p + 6 = 3p - 9 Or, 'p' = 15 Quantity I: Present age of 'Chintu' = 2p - 6 = 2 × 15 - 6 = 24 years So, Quantity I = 24 years Quantity II: Average present age = (1/3) × (p - 3 + p + 2p - 6) = (1/3) × (4p - 9) = (1/3) × (4 × 15 - 9) = (51/3) = 17 years So, Quantity II = 17 years Therefore Quantity I > Quantity II

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