Question
The sum of ages of A, B and C is 65 years.The ratio
between age of A, 4 years hence and the present age of B is 5:6. Quantity I: 414 Quantity II: 6 times the sum of ages of B and C . In the question, two quantities I and II are given. You have to solve both the quantities to establish the correct relation between Quantity-I and Quantity-II.Solution
ATQ, Given, The sum of ages a + b + c = 65 and (a+4)/b = 5/6, leading to 6a−5b=−24. For Quantity II: Quantity II = 6 × (65−a) = 390 − 6a From 6a = 5b − 24, 'a' is expressed in terms of 'b', making 390 − 6a less than 414 for positive 'b'. So, Quantity I > Quantity II.
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