Question
Quantity 1 : A and B together can paint a wall in 12
hours. A alone can paint it in 18 hours. B paints for 5 hours, and then A completes the remaining work. How many total hours did they take to paint the wall? Quantity 2 : X and Y together can paint a wall in 14 hours. X alone can paint it in 20 hours. Y paints for 8 hours, and then X completes the remaining work. How many total hours did they take to paint the wall?Solution
For Quantity 1 : A’s rate = 1/18, B’s rate = 1/12 - 1/18 = 1/36 Work done by B in 5 hours = 5 × 1/36 = 5/36 Remaining work = 1 - 5/36 = 31/36 Time taken by A to finish remaining work = (31/36) ÷ (1/18) = 15.5 hours Total time = 5 + 15.5 = 20.5 hours Quantity 1 = 20.5 hours For Quantity 2 : X’s rate = 1/20, Y’s rate = 1/14 - 1/20 = 3/140 Work done by Y in 8 hours = 8 × 3/140 = 6/35 Remaining work = 1 - 6/35 = 29/35 Time taken by X to finish remaining work = (29/35) ÷ (1/20) = 16.57 hours Total time = 8 + 16.57 = 24.57 hours Quantity 2 = 25.71 hours Correct option : b) Quantity 1 < Quantity 2
What is the total number of work hours reported by employees in the Sales department?
What will come in the place of question mark in the given expression?
√(16 2 + 3 of 11) + 21% of 300 = ? 2 of 5
The set of all bijective functions from a finite set A to itself forms:
A car travels 300 km at a speed of 60 km/h and another 200 km at a speed of 80 km/h. Find the approximate average speed of the car for the entire journey.
A rectangular park is 120 m long and 80 m wide. A path of uniform width is constructed inside the park. If the area of the path is 3600 m², find the wi...
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y and choose the...
X, Y, and Z entered into a partnership with initial investments of Rs. (M + 2500), Rs. 3M, and Rs. (4M - 20000), respectively. After 6 months, W joined ...
A trader buys 400 shares of a company at Rs. 80 each, paying 1% brokerage on the purchase value. The company declares a dividend of 12% on the face valu...
Solve log₂(x–1) + log₂(x+3) = 3.
The difference between the lengths of two parallel sides of a trapezium is 12 cm. The perpendicular distance between these two parallel sides is 60 cm. ...
