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    Question

    Quantity I: The age of A is sixteen times that of her

    son B. If the age of B is 4 years, what is the age of A? Quantity II: The ratio between the present ages of S and T is 4:3. 6 years ago the ratio between their ages was 7 : 5. What will be S’s age after 16 years? Study the following information carefully and answer the Questions given below:
    A Quantity I > Quantity II Correct Answer Incorrect Answer
    B Quantity I ≥ Quantity II Correct Answer Incorrect Answer
    C Quantity II > Quantity I Correct Answer Incorrect Answer
    D Quantity II ≥ Quantity I Correct Answer Incorrect Answer
    E Quantity I = Quantity II or Relation cannot be established Correct Answer Incorrect Answer

    Solution

    I : Ratio A : B =  16:1 since 1 = 4 so 16 = 16*4 =64 years. II : 4 : 3   ….(1) 7 : 5   ( 6 yrs ago)      …. (2) To make the ratio equal multiply (1) by 2 8 : 6 7 : 5 now difference is 1 (6-5=1, 8-7 = 1) so 1 = 6 So present age of S = 6 × 8 =  48yr After 16 yrs S’s age = 48 + 16 = 64 years

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