Question
Quantity I: The age of A is sixteen times that of her
son B. If the age of B is 4 years, what is the age of A? Quantity II: The ratio between the present ages of S and T is 4:3. 6 years ago the ratio between their ages was 7 : 5. What will be S’s age after 16 years? Study the following information carefully and answer the Questions given below:Solution
I : Ratio A : B = 16:1 since 1 = 4 so 16 = 16*4 =64 years. II : 4 : 3  ….(1) 7 : 5  ( 6 yrs ago)     …. (2) To make the ratio equal multiply (1) by 2 8 : 6 7 : 5 now difference is 1 (6-5=1, 8-7 = 1) so 1 = 6 So present age of S = 6 × 8 = 48yr After 16 yrs S’s age = 48 + 16 = 64 years
85.22 of 499.98% + 299.99 ÷ 30.18 = ?
783 ÷ 42.59 × 25.86 =?
118.95 – 24.10 + (91.90 ÷ 22.89 × 12.14) = ?
What approximate value will come in place of the question mark (?) in the following question?(Note: You are not expected to calculate the exact value.)<...
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
? = 16.08 + 13.99 × 25.07
(23.99)2 – (17.99)2 + (1378.88 + 44.88) ÷ ? = 607.998
25.31% of 5199.90 + (19.9 × 17.11) + 46.021 =? + 168.98
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
?% of (144.31 ÷ 17.97 × 60.011) = 239.98
Relevant for Exams:
