Quantity I: The age of A is sixteen times that of her son B. If the age of B is 4 years, what is the age of A?

Quantity II: The ratio between the present ages of S and T is 4:3. 6 years ago the ratio between their ages was 7 : 5. What will be S’s age after 16 years?

(?)² + 9.11³ = 31.9² – 39.03 

540.11 ÷ 17.98 × 5.14 – 131.9 = √? 

(6859.01)^1/3  × 10.11 × 14.47 ÷ 20.32 = ? + 45.022

(15.022% of 20) × 46 ÷ 2.03 – 8.78 × 5.72 + 50.23% of 4820 = ?

16.01^{(? × 8.09 ÷ 16.09)} = 3.01 of 69.69 + 14.12 of 4.01 - 100.998 of 2.19

9.99% of 19.86% of 30.23% of (11999.84 × 9.68) = ?

(29.97%) of 9840 + ? + (45.17% of 1240) = (31.955% of 11750)

15.001% of 799.99 - 3/11% of 1099.99 + 111.002 = ?

– (8.002)³ + (30.001)² - (4.01)⁴ =?

?³ - (77.98 ÷ 6.09 + 10.12)² + (2.01⁵ - 11.983)² = 20.01 × (215.98^(2/3) - √36.03)