Question

Quantity-I: A mixture contains 40% milk and the rest

Q: Answer- Quantity-I: A mixture contains 40% milk and the rest 240 litres water. When (x−10) litres of water...

ATQ, Quantity I Initial quantity of milk 2400.400.60160 litres Final quantity of milk 160x8168x litres Final quantity of water 240x10230x litres According to the question, 168x230x 78 8168x7230x 13448x16107x x266 So, Quantity I 266 Quantity II Let the initial quantity of alcohol and water be 6x litres and 4x litres, respectively Final quantity of alcohol 0.706x54.2x5 litres Final quantity of water 0.704x72.8x7 litres According to the question, 4.2x52.8x7 86 64.2x582.8x7 25.2x3022.4x56 2.8x26 262.8 9.29 Therefore, y 0.25 4x x So, Quantity II 9.29 So, Quantity I Quantity II

240 litres water. When (x−10) litres of water and (x+8) litres of milk are added to this mixture, the ratio of the quantity of milk to that of water in the resultant mixture becomes 7:8. Find the value of ‘x’. Quantity-II: The ratio of the quantity of alcohol to that of water in a mixture (alcohol + water) is 6:4, respectively. 30% of this mixture is replaced with 5 litres of alcohol and 7 litres of water such that the ratio of the quantity of alcohol to that of water in the resultant mixture becomes 8:6. If the measure of 25% of the initial quantity of water in the mixture is ‘y’ litres, then find the value of ‘y’. In the question, two Quantity I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantity-II and choose the correct option.

A Quantity-I > Quantity-II

B Quantity-I < Quantity-II

C Quantity-I ≤ Quantity-II

D Quantity-I = Quantity-II or No relation

E Quantity-I ≥ Quantity-II

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