Question
In the question, two quantities i.e. Quantity I and
Quantity II are given. Solve the given quantities to establish the correct relation between them and choose the correct option. Quantity I: V and K venture into a construction business, deploying their capital in the ratio of 17:12, respectively. Their investment spans time in the ratio of 12:19. If K's share of the profit amounts to Rs. 741, then determine the combined total profit earned by V and K. Quantity II: A shopseller brought an item.1, elevating its marked price by a 70%. Upon selling it and applying successive discounts of 20% and 25%, the final selling price is Rs. 918. Uncover the cost of item.2, with a cost price 35% higher than that of item.1.Solution
ATQ, Quantity I Profit Ratio, V:K = (17 × 12) : (12 × 19) = 17 : 19 Total Profit = 741 × (36/19) = Rs.1404 Quantity II CP of item.1= {918/(0.75 × 0.8 × 1.7)} = (918/1.02) = Rs.900 CP of item.2 = 900 × 1.35 = Rs.1215 Hence, Quantity I > Quantity II
I: x2Â + 31x + 228 = 0
II: y2 + 3y – 108 = 0
I. x² - 33x + 270 = 0
II. y² - 41y + 414 = 0
I. 5x² + 17x + 6 = 0                     Â
II. 2y² + 11y + 12 = 0
...I. 195x² - 46x - 21 = 0
II. 209y² + 7y - 12 = 0
I. 3x2 - 16x - 12 = 0
II. 2y2 + 11y + 9 = 0
I. 8x² + 2x – 3 = 0
II. 6y² + 11y + 4 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. 27(p + 2) = 2p(24 – p)
II. 2q2 – 25q + 78 = 0
I. 5x² -14x + 8 = 0 Â
II. 2y² + 17y + 36 = 0  Â
What is the nature of the roots of the quadratic equation x² – 5x + 7 = 0 ?Â
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