What is the minimum possible number of chocolates a boy can buy, if there must be atleast one chocolate of each kind? Quantity
I. The shop has three different kinds of chocolates costing Rs.2, Rs.5, Rs. 10.  The boy spends total Rs. 120 on the chocolates. Quantity
II. The shop has three different kinds of chocolates costing Rs.3, Rs.6, Rs. 11.  The boy spends total Rs. 145 on the chocolates.

Quantity I. Minimum number of chocolates are possible when purchases maximum number of costliest chocolates. Rs 100 must be spent on 10 chocolates = 10 × 10, 2 chocolates @ Rs. 5 each = 2 × 5 = 10 and 5 chocolates @ Rs. 2 each = 2 × 5 = 10 Thus, minimum number of chocolates = 10 + 2 + 5 =17 Quantity II. Minimum number of chocolates are possible when purchases maximum number of costliest chocolates. Rs 121 must be spent on 11 chocolates = 11 × 11 =  121, 3 chocolates @ Rs. 6 each = 3 × 6 = 18 and 2 chocolates @ Rs. 3 each = 2 × 3 = 6 Thus, minimum number of chocolates = 11 + 3 + 2 =16 Hence Quantity I > Quantity II