Question
In ΔPQR, ∠Q is a right angle. If PQ = 15 cm and QR = 20
cm, find the length of the circumradius of triangle PQR.Solution
ATQ,
We know that in a right-angled triangle, the circumcentre lies at the midpoint of the hypotenuse.
So, circumradius of the triangle = PR ÷ 2
Using Pythagoras theorem, we have:
PR² = PQ² + QR²
Or, PR² = 15² + 20²
Or, PR = √(225 + 400) = √625
So, PR = 25
So, required circumradius = 25 ÷ 2 = 12.5 cm
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