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Let the total work be LCM (20, 30) = 60 units
Efficiency of Amit = 60 / 20 = 3 units/day
Efficiency of Bhavya = 60 / 30 = 2 units/day
Work done in 3 days = Bhavya (2×1) + Amit (3×1) + Both (5×1) = 2 + 3 + 5 = 10 units
In 3×5 = 15 days (5 full cycles), work = 10 × 5 = 50 units
Remaining work = 60 - 50 = 10 units
Next 2 days work = Bhavya (2) + Amit (3) = 5 units
Remaining = 10 - 5 = 5 units
Next day (both) do 5 units → full day
Total time = 15 (full cycles) + 2 + 1 = 18 days
16 23 31 40 50 61 ?
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