Question
The speed of boat 'Y' in still
water is the same as the downstream speed of boat 'X'. Boat 'X' requires 1 hour longer than boat 'Y' to travel 80 km downstream. If the speed of the current is 4 km/hr, what is the speed of boat 'Y' in still water?Solution
ATQ, Let the speed of boat 'X' in still water be βaβ km/hr Downstream speed of boat X = βa + 4β km/hr Speed of boat Y in still water = (a + 4) km/hr According to the question, 80/(a + 4) β 80/(a + 4 + 4) = 1 Or, a2 + 12a β 288 = 0 Or, a2 + 24a β 12a β 288 = 0 Or, a(a + 24) β 12(a + 24) = 0 Or, (a β 12)(a + 24) = 0 Therefore, a = 12, -24 Speed cannot be negative Therefore, speed of boat X in still water = 12 km/hr Speed of boat Y in still water = 12 + 4 = 16 km/hr
((67)32 × (67)-18 / ? = (67)βΈ
What will come in the place of question mark (?) in the given expression?
?% of (112 X 3 + 164) + 75 = 2 X 140 + 35
20% of 450 - 15% of 400 = 25% of ?
β121 + β961β β289 =?2
45% of 1020 + ?% of 960 = 747
(γ(0.4)γ^(1/3)Β Γ γ(1/64)γ^(1/4)Β Γ γ16γ^(1/6)Β Γ γ(0.256)γ^(2/3))/(γ(0.16)γ^(2/3)Β Γ 4^(-1/2)Β Γγ1024γ^(-1/4) ) = ?
(512) (2/3) Γ β64 Γ· (512) (1/3) = (64) (?/2) Γ· (2)6Β
1231 + 1312 + 2113 β 3211 = ?
Simplify the following expression:-
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