Question
Train X is moving at a relative speed of 288 km/hr with
respect to Train Y, which is approaching from the opposite direction. The two trains completely pass each other in 3 seconds. Given that both trains have the same length, determine the length of each train.Solution
ATQ,
Let the length of each train be 'm' metres. Relative speed = 288 × 5/18 = 80 m/s According to the question, 2m/80 = 3 Or, m = 120 metresÂ
9/5 × 18/25 ÷ 42/21 = ? - 82/75
15 × 18 + 25 × 12 + 30 × 24 = ?% of 1720
√324 * 6 – 20% of 180 + ? = 130% of 150
400 % of 20 + 65 % of 620 - 92 × 5 = ?
- Find the value of the expression:
15 + 10 – 6 × [20 + 8 – 2 × (50 – 35)] What will come in place of (?) in the given expression.
(3/4 of 64) + (1/2 of 48) = ?If 1210 ÷ 22 + 1332 ÷ 37 - y + 54 × 3 = 980 ÷ 20 × 144 ÷ 48, then the value of y is:
600 ÷ 8 + 12 % of 250 + ? * 14 = 50 * √49
What will come in the place of question mark (?) in the given expression?
23 X 35 - ? = (132 + 16) X 3 + 25
- What will come in the place of question mark (?) in the given expression?
435 + 729 - 282 x 2 = ? + 225 + 125