Question
Two years from now, a father's age will be twice the age
his son was two years ago. Additionally, four years ago, the ratio of the father's age to the son's age was 19:10. What is the son's current age?Solution
4 years ago from now, let the ages of the father and the son be '19x' years and '10x' years, respectively Age of the father, 2 years hence from now = 19x + 4 + 2 = (19x + 6) years Age of the son, 2 years ago from now = 10x + 4 - 2 = (10x + 2) years According to the question, 19x + 6 = (10x + 2) X 2 Or, 19x + 6 = 20x + 4 Or, x = 2 Therefore, present age of the son = 10x + 4 = 10 X 2 + 4 = 24 years
- 44.83% of 799.88 + (84.12 X 14.98 ÷ 62.87) = ?² + 55.65
15.232 + 19.98% of 649.99 = ? × 4.99
20.22% of (61.9 × 5.01) + 69.97 =?Â
14.232 + 19.98% of 629.99 = ? × 6.99
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
(1120.45 ÷ 15.89) × 11.34 = ? × 4.78
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
999.99 + 99.99 + 99= ?
(33.95)2 – (25.004)2 + (18.0099)2 – (9.07)2 = ? - (14.990)2
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