Question
Two years from now, a father's age will be twice the age
his son was two years ago. Additionally, four years ago, the ratio of the father's age to the son's age was 19:10. What is the son's current age?Solution
4 years ago from now, let the ages of the father and the son be '19x' years and '10x' years, respectively Age of the father, 2 years hence from now = 19x + 4 + 2 = (19x + 6) years Age of the son, 2 years ago from now = 10x + 4 - 2 = (10x + 2) years According to the question, 19x + 6 = (10x + 2) X 2 Or, 19x + 6 = 20x + 4 Or, x = 2 Therefore, present age of the son = 10x + 4 = 10 X 2 + 4 = 24 years
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