Question
Amit can complete a task alone in
20 days. Bheema and Chetna, working together, can complete the same task in 12 days. The ratio of their efficiencies is 2:3. What is the time it will take for Amit and Bheema to complete the work together?Solution
ATQ, Let total work be 60 units. {LCM (20 and 12)} So, efficiency of 'Amit' = 60 ÷ 20 = 3 units/day And combined efficiency of 'Bheema' and 'Chetna' = 60 ÷ 12 = 5 units/day So, efficiency of 'Bheema' = 5 × (2/5) = 2 units/day So, required time = 60 ÷ (3 + 2) = (60/5) = 12 days
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