Question
Amit can complete a task alone in
20 days. Bheema and Chetna, working together, can complete the same task in 12 days. The ratio of their efficiencies is 2:3. What is the time it will take for Amit and Bheema to complete the work together?Solution
ATQ, Let total work be 60 units. {LCM (20 and 12)} So, efficiency of 'Amit' = 60 ÷ 20 = 3 units/day And combined efficiency of 'Bheema' and 'Chetna' = 60 ÷ 12 = 5 units/day So, efficiency of 'Bheema' = 5 × (2/5) = 2 units/day So, required time = 60 ÷ (3 + 2) = (60/5) = 12 days
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
Relevant for Exams:
