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Given sin A + cos A = 1. Squaring both sides: (sin A + cos A)² = 1² sin² A + cos² A + 2 sin A cos A = 1. Since sin² A + cos² A = 1, we have: 1 + 2 sin A cos A = 1. Thus, 2 sin A cos A = 0, which implies sin 2A = 0 Therefore, tan A = 0.
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