Question
Solve the quadratic equations and determine the relation
between x and y: Equation 1: 2x² - 10x + 12 = 0 Equation 2: y² - 8y + 15 = 0Solution
From equation 1: 2x² - 10x + 12 = 0 Dividing by 2: x² - 5x + 6 = 0 Factorizing: (x - 3)(x - 2) = 0 So, x = 3 or x = 2. From equation 2: y² - 8y + 15 = 0 Factorizing: (y - 5)(y - 3) = 0 So, y = 5 or y = 3. Comparing x and y: • If x = 3 and y = 5, x < y. • If x = 2 and y = 5, x < y. • If x = 3 and y = 3, x = y. Thus, x ≤ y. Answer: D
The respective ratio of the present ages of A and B is 7:6. The present age of C is 10% more than that of B. The sum of the present ages of A, B and C i...
The ratio of the present ages of P and Q is 7:4 respectively. If the age of P 15 years hence from now will be 125% more than the age of Q 4 years ago fr...
Four years ago, the ratio of ages of ‘Ravi’ and his sister was 3:4, respectively. 4 years from now, the ratio of ages of Ravi and his mother will be...
Pintu' is father of 'Qasim'. '2x' years ago from now, the age of 'Pintu' was four times the age of 'Qasim'. While, '2x' years hence from now, age of 'Pi...
The ratio of age of A and his son is 5:2. If the difference of their ages 4 year ago is 21, then find the sum of ages of A and his son 9 year hence?
The average age of (x + 3) students is 20 years. When their teacher aged 35 years joins them, the average increases by 1 year. Find x% of 400.
A’s age is 180% of what he was 5 years ago, But 90% of what it will be after 5 years. What is his present age?
The ratio of the present ages of father and his son is 9:5. The product of their ages 3 years ago was 33 times of his son’s age that year. What wa...
The ratio of age of ‘B’ after 6 years from now and age of ‘C’ 4 years ago from now is 7:4, respectively. The present age of ‘C’ is 20% of th...
M and S currently have ages in the ratio of 3:4. R's present age is 50% more than S's present age. The ratio of M's age one year from now to R's age thr...
