Let the parallelogram be ABCD, AB = 3 cm BC = 10 cm CD = 3 cm DA = 10 cm Using the concept, The sum of the squares of the diagonals = (AB + BC + CD + DA ) ⇒ (32 + 102 + 32 + 102 ) ⇒ (9 + 100 + 9 + 100) ⇒ 218
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