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ATQ,
From I:
x³ = -1331
x = -11
From II:
y² + 23 + 132 = 0
y² + 11y + 12y + 132 = 0
y(y + 11) + 12(y + 11) = 0
(y + 11)(y + 12) = 0
y = -11, -12
So, x ≥ y
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