Question

    I. y/16 = 4/y II. x3 = (2 ÷

    50) × (2500 ÷ 50) × 42 × (192 ÷ 12) In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
    A If x > y Correct Answer Incorrect Answer
    B If x ≥ y Correct Answer Incorrect Answer
    C If x < y Correct Answer Incorrect Answer
    D If x ≤ y Correct Answer Incorrect Answer
    E If x = y or the relationship cannot be established Correct Answer Incorrect Answer

    Solution

    I. y/16 = 4/y y 2 = 16 × 4 y 2 = 64 y = ± 8 II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12) x3 = 2/50 × 2500/50 × 42 × 192/12 x3 = 512 x = 8 Hence, x ≥ y

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