Question
I. y/16 = 4/y II. x3 = (2 ÷
50) × (2500 ÷ 50) × 42 × (192 ÷ 12) In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. y/16 = 4/y y 2 = 16 × 4 y 2 = 64 y = ± 8 II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12) x3 = 2/50 × 2500/50 × 42 × 192/12 x3 = 512 x = 8 Hence, x ≥ y
More Quadratic equation Questions
- Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___ - Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN
Relevant for Exams:
