Question
I. y/16 = 4/y II. x3 = (2 ÷
50) × (2500 ÷ 50) × 42 × (192 ÷ 12) In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. y/16 = 4/y y 2 = 16 × 4 y 2 = 64 y = ± 8 II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12) x3 = 2/50 × 2500/50 × 42 × 192/12 x3 = 512 x = 8 Hence, x ≥ y
For given pair of equations, how many solutions are possible?
3x + 4y = 15 and 6x + 8y = 10
For given pair of equations, how many solutions are possible?
4x + 6y = 16 and 8x + 12y = 32
The ratio of roots of the equation mx2 + nx + n = 0 is α/ β = a/b, then find the value of `sqrt(a/b)+sqrt(b/a)+sqrt(n/m)`
Find the area between the lines 18x +12y = 108, 9x  + 6y  = 27, x - axis and y -axis.Â
If in two linear equations ax + by = c and dx + ey = f and a/d = b/e = c/f then, which of the following is true about the two equations?
For which value of m, there is no solution to the equation -
a – b = 5
ma – 4b = 1
The lines x + y = 9 and x - y = 3 intersect at point P. Find the coordinates of P.
Solve: (x/3) + (x/5) = 16
Find the value of 'a' and 'b' which satisfy the following equations:
9a + 7b = 30
4a - 5b = 62
If (5√P - 7√Q) = 5, [1.5P = 4Q-(R/3)+9] and (√P/√Q) = 1.6, then find out the value of ‘R’.