Question
I. y/16 = 4/y
I. y/16 = 4/y
II. x3 = (2 ÷ 50) × (2500 ÷ 50) × 42 × (192 ÷ 12)
In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
More Quadratic equation Questions
- In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between x and y. I. x2 = 196 II...
- I. 2x² - 11x + 12 = 0 II. 12y² + 29y + 15 = 0
- Two quadratic equations I and II are given below. Equation I: ax² - 33x + ab = 0 Equation II: cy² - 34y + 2cd = 0 Note: (i) Sum of the values of 'a' an...
- I. 15y2 + 26y + 8 = 0 II. 20x2 + 7x – 6 = 0
- I. 5x + 2y = 31 II. 3x + 7y = 36
- Find the coefficient of x³ in (2x − 3)⁶.
- I. 4p² + 17p + 15 = 0 II. 3q² + 19q + 28 = 0
- Two quadratic equations I and II are given below. Equation I: ax² − 38x + ab = 0 Equation II: cy² − 65y + 2cd = 0 Note: (i) Sum of the values of a and ...
- I. 20x² - 93x + 108 = 0 II.72y² - 47y - 144 = 0
- I. x² – 44x + 468 = 0 II. y² – 30y + 216 = 0
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt