Question
I). p2 - 20p + 51 = 0, II).
2q2 - 7q + 6 = 0 The following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give the answer.Solution
ATQ, p2 - 20p + 51 = 0 or p2 - 17p - 3p – 51 = 0 or, (p - 17) × (p - 3) = 0 or, p = 17, 3 2q2 - 7q + 6 = 0 Or 2q2 - 4q - 3q + 6 = 0 Or (q - 2) × (2q - 3) = 0 Or, q = 2, 3/2 So, p > q
I. 2x2 – 5x – 63 = 0
II. 2y2 – 7y – 72 = 0
I. 18p²- 21p + 6 = 0
II. 16q² - 24q +9 = 0
I. 15/(√x)+9/(√x)=11√x
II. (√y)/4 + (5√y)/12 = 1/(√y)
I. 6p2 – 7p = 5p – 7p2 + 25
II. 11q2 – 63q + 90 = 0
In each of these questions, two equations (I) and (II) are given.You have to solve both the equations and give answer
I. x² - 8x + 15 = 0 ...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 37x² - 172x + 135 = 0
Equation 2: 29y² - 132y + ...
I. 20y² - 13y + 2 = 0
II. 6x² - 25x + 14 = 0
Quantity I: The cash price of a notebook is Rs. 100 but is can also be purchased on 11 monthly equal instalments of Rs. 10 each. Find rate of S.I.?
...I. 2y2 - 37y + 143 = 0
II. 2x2 + 15x – 143 = 0
I. x2 + (9x/2) + (7/2) = - (3/2)
II. y2 + 16y + 63 = 0
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