Question
I). p2 - 20p + 51 = 0, II).
2q2 - 7q + 6 = 0 The following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give the answer.Solution
ATQ, p2 - 20p + 51 = 0 or p2 - 17p - 3p – 51 = 0 or, (p - 17) × (p - 3) = 0 or, p = 17, 3 2q2 - 7q + 6 = 0 Or 2q2 - 4q - 3q + 6 = 0 Or (q - 2) × (2q - 3) = 0 Or, q = 2, 3/2 So, p > q
799.99 + 1500.12 Ă· 29.98 Ă— 50.01 = ? Ă— 24.96
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