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      Question

      I. x2 + 13x + 42 = 0 II. y² + 13y

      + 40 = 0 In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
      A if x>y Correct Answer Incorrect Answer
      B if x Correct Answer Incorrect Answer
      C if x≥y Correct Answer Incorrect Answer
      D if x=y or relationship cannot be established. Correct Answer Incorrect Answer

      Solution

      I. x2 + 13x + 42 = 0 => x2 + 7x + 6x + 42 = 0 => x(x + 7) + 6(x + 7) = 0 => (x + 7) (x + 6) = 0 => x = -7, -6 II. y² + 13y + 40 = 0 => y2 + 8y + 5y + 40 = 0 => y(y + 8) + 5(y + 8) = 0 => (y + 8) (y + 5) = 0 => y = -8, -5 Hence, the relationship cannot be established between x and y.

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