📢 Too many exams? Don’t know which one suits you best? Book Your Free Expert 👉 call Now!
  • google app store apple app store
    • ✖

      Question

      I. 4x2 + 9x - 9 = 0 II. 4y2

      - 19y + 12 = 0 In each of the following questions, there are two equations. You have to solve both equations and mark the correct answer.
      A if x > y Correct Answer Incorrect Answer
      B if x < y Correct Answer Incorrect Answer
      C if x ≥ y Correct Answer Incorrect Answer
      D if x ≤ y Correct Answer Incorrect Answer

      Solution

      I. 4x2 + 9x - 9 = 0 => 4x2 + 12x – 3x – 9 = 0 => 4x(x + 3) – 3(x + 3) = 0 => (x + 3) (4x -3) = 0 => x = -3, 3/4 II. 4y2 - 19y + 12 = 0 => 4y2 - 16y – 3y + 12 = 0 => 4y(y - 4) – 3(y - 4) = 0 => (y - 4) (4y – 3) = 0 => y = 4, 3/4 Hence, x ≤ y.

      Practice Next
      More Quadratic equation Questions

      Relevant for Exams:

      ask-question