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    Question

    I. 821

    style='mso-bidi-font-weight: normal'> x x² - 757 x² = 256 II. √196 y³ - 12 y³ = 16 Directions (Q.21-25): In the following questions, two equations numbered I and II are given. You have to solve both the equations and find out the correct option. Give answer
    A If x ≥y Correct Answer Incorrect Answer
    B If x ≤y Correct Answer Incorrect Answer
    C If x>y Correct Answer Incorrect Answer
    D If x Correct Answer Incorrect Answer
    E If x=y or relationship between between x and y cannot be established Correct Answer Incorrect Answer

    Solution

    I. 821 x ² - 757 [if gte msEquation 12]> x [if !msEquation]--> [endif]--> x² = 256 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 64 x ² = 256 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> x ² = 4 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> , [if gte msEquation 12]>x [if !msEquation]--> [endif]--> x = `+-` 2 II. √196 y [if gte msEquation 12]>y [if !msEquation]--> [endif]-->³ - 12 [if gte msEquation 12]> y [if !msEquation]--> [endif]--> y³ = 16 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 14 y ³ - 12 [if gte msEquation 12]>y [if !msEquation]--> [endif]--> y³ = 16 [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> 2 y ³ = 16 , y [if gte msEquation 12]>⇒ [if !msEquation]--> [endif]--> = 2 Hence, x `<=` y

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