I. 4x² - 15x + 9 = 0 4x² - 12x - 3 x + 9 = 0 4 x(x – 3) – 3 (x – 3) = 0 (4 x – 3) (x – 3) = 0 ∴ x = 3, 3/4 II. 20y² - 23y + 6 = 0 20y² - 8y - 15 y + 6 = 0 4 y(5 y – 2) – 3(5 y - 2) = 0 (4 y - 3) (5 y – 2) = 0 ∴ y = 2/5 ,3/4 Hence, x≥y
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