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      Question

      I. 10x² - 11x + 3 = 0 II. 42y² - 23y

      – 10 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
      A if x>y Correct Answer Incorrect Answer
      B if x≥y Correct Answer Incorrect Answer
      C if x Correct Answer Incorrect Answer
      D if x ≤y Correct Answer Incorrect Answer
      E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

      Solution

      I. 10x² - 11x + 3 = 0 10x² - 6 x - 5 x + 3 = 0 2 x (5 x - 3) – 1(5 x - 3) = 0 (2 x – 1)(5 x - 3) = 0 ∴ x = 1/2, 3/5 II. 42y² - 23y – 10 = 0 42y² - 35y + 12 y – 10 = 0 7 y(6 y – 5) + 2(6 y – 5) = 0 (7 y + 2)(6 y – 5) = 0 ∴ y = -2/7, 5/6 Hence, relationship cannot be established between x and y

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