Question
I. 8y² - 6y – 9 = 0 II. 6 x² - x
– 12 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.Solution
I. 8y² - 6y – 9 = 0 8y² + 12 y - 6y – 9 = 0 4 y(2 y + 3) - 3 (2y+3)= 0 (4 y – 3) (2 y + 3) = 0 ∴ y = -3/2, 3/4 II. 6 x² - x – 12 = 0 6 x² - 9x + 8 x – 12 = 0 3 x (2 x – 3) + 4(2 x – 3) = 0 (2 x – 3) (3 x + 4) = 0 (2 x – 3) (3 x + 4) = 0 ∴ x = 3/2, -4/3 Hence, relationship cannot be established between x and y
230 192 172 ? 122 100
...What value should come in the place of (?) in the following number series?
64, 80, 104, ?, 176, 224
97, 106, ?, 195, 411, 460
What will come in place of the question mark (?) in the following series?
29, 42, ?, 95, 135, 184
Find the missing term:
2, 6, 15, 31, 56, ?
32   48   96   ?   720   2520
82, 98, 130, 178, 242, ?
4 10 ? 62.5 156.25 390.625
...140, 146, 170, 224, ?, 470
7 47 ? 223 359 527
...
Relevant for Exams:
