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      Question

      I. 8y² - 6y – 9 = 0 II. 6 x² - x

      – 12 = 0 In the following questions, two equations numbered I and II are given. You have to solve both the equations and give answer.
      A if x>y Correct Answer Incorrect Answer
      B if x≥y Correct Answer Incorrect Answer
      C if x Correct Answer Incorrect Answer
      D if x ≤y Correct Answer Incorrect Answer
      E if x=y or the relationship cannot be established Correct Answer Incorrect Answer

      Solution

      I. 8y² - 6y – 9 = 0 8y² + 12 y - 6y – 9 = 0 4 y(2 y + 3) - 3 (2y+3)= 0 (4 y – 3) (2 y + 3) = 0 ∴ y = -3/2, 3/4 II. 6 x² - x – 12 = 0 6 x² - 9x + 8 x – 12 = 0 3 x (2 x – 3) + 4(2 x – 3) = 0 (2 x – 3) (3 x + 4) = 0 (2 x – 3) (3 x + 4) = 0 ∴ x = 3/2, -4/3 Hence, relationship cannot be established between x and y

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