Question
I. 64x2 - 64x + 15 Â = 0 Â Â Â Â II.
21y2 - 13y + 2Â =0 In the following questions two equations numbered I and II are given. You have to solve both the equations. Give answer if;Solution
I. 64x - 64x + 15  = 0  64x - 24x - 40x + 15 = 0  8x (8x - 3 ) - 5 ( 8x - 3 ) = 0 (8x - 5 ) ( 8x - 3) = 0 x = `(3)/(8)`  , `(5)/(8)` II. 21y2 - 13y + 2  =0   21y2 - 7y - 6y + 2 = 0   7y ( 3y - 1 ) -2 ( 3y - 1 ) = 0   y = `(2)/(7)`  , `(1)/(3)` Hence, x > y
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