Question
The wheel of an engine 5 (1/9) metersĀ in circumference
makes five revolutions in 4 seconds. Find the speed of the train in km per hour.Solution
5 revolution = 4 seconds Then, 1 revolution = 4/5 seconds Speed = Distance/Time = [(46Ā Ć 5 )/(9Ā Ć 4)]Ā Ć (18/5) =Ā 23 km/hr
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Find the range of the given data:
14, 28, 35, 21, 42, 56, 49
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